The bulb absorbs the high peak values of the voltage and provides a relatively controlled output to the battery, which becomes self regulatory through the glow of the filament intensity of the bulb (varying resistance). To blunt of this peak value, we introduce a bulb in series with the circuit. Though the RMS value of this voltage may appear to be 12V, the peak voltage is still 24V, therefore it cannot be applied directly to the battery. When the power is switched ON, the 1N5402 diode rectifies the 24V DC to produce half wave 24V DC at the output. The functioning of the circuit may be explained in the following manner: That means if the battery is 12V, the transformer should be 24V, and if the AH of the battery is 7.5 then dividing this by 10 gives 750mA which becomes the recommended charging rate of the battery, multiplying this by 2 gives 1.5Amps, so this becomes the required current rating of the transformer.Īfter you have collected all the above material, you may simply connect the above parameters together with the help of the diagram. A transformer having voltage rating equal to twice that of the battery voltage and current twice the charging rate of the battery.
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